AB=AC,AE=AD,∠EAB=∠DAC,那么BE与CD相等吗?为什么?图————E、F是AC上的两点,AF=CE,BF=DE,DE‖BF,那么AB与CD相等吗?为什么图————
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已知如图,AE=AC,∠E=∠C,∠EAB=∠CAD,求证:AB=AD
如图,AC=AB,AE=AD,∠EAB=∠DAC,求证:BD=CE
已知:如图,AE=AC,AB=AD,∠EAB=∠CAD 已知:如图,AE=AC,AB=AD,∠EAB=∠CAD已知:如图,AE=AC,AB=AD,∠EAB=∠CAD 求证:①△ABC全等于△ADE;②∠1=∠2
如图AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证:△DAC≌三角形EAB
已知如图,AE=AC,AB=AD,∠EAB=∠CAD,试说明:∠B=∠D图:
已知:AE=AC,AB=AD,∠EAB=∠CAD.试说明∠B=∠D.(SAS)
如图,已知AB=AC,AE=AD,∠EAB=∠DAC,那么BE与CD相等吗?为什么?
如图,已知AB=AC,AE=AD,∠EAB=∠DAC,那么BE与CD相等吗,为什么
AD是三角形ABC的外接圆的切线,过B引AD的平行线交AC的延长线于E.求证:AB的平方等于AC乘以AE∵AD//BE∴∠DAC = ∠E∵DA是圆O的切线∴∠DAC = ∠ABC∴∠ABC = ∠E∵∠BAC = ∠EAB∴△ABC∽△AEB∴AC:AB = AB
如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE,求证:(1)△DAC≌△EAB;(2)BE⊥CD. ,の
如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE,已知△DAC≌△EAB.求证BE⊥CD
已知:如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证:△DAC≌△EAB.可能不太好看,
DA⊥AB EA ⊥AC AB=AD AC=AE 求证 DC=BE
如图,在△ABC中,AB=AC,AD⊥BD,AE⊥CE,且AD=AE,BD和CE交于点O.说明∠EAB=∠DAC
如图,在△ABC中,AB=AC,AD⊥BD,AE⊥CE,且AD=AE,BD和CE交于点O.说明∠EAB=∠DAC的理由
如图,在△ABC中,AB=AC,AD⊥BD,AE⊥CE,且AD=AE,BD和CE相交于O,请说明∠EAB=∠DAC的理由.
已知:如图,AB=AC,AD=AE,角EAB=角DAC.求证:角D=角E.
已知:如图,AB=AC,AD=AE,角EAB=角DAC.角D=角E.