设函数f(x)=3sin(wx+π/6),w>0,x属于（负无穷大,正无穷大）,且以π/2为最小正周期若f(a/4+π/12)=9/5,则sina的值为什么为正负4/5?

设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sin(2wx+π/6)+1/2,（其中0 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 老师好：设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f(x)=sin(wx+g)+cos(wx+g) (w>0,|g| 设函数f(x)=sin(wx+q)+cos(wx+q)(w>0,q的绝对值 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f（x）=sin（wx+φ）（w>0,-π/2 设函数f(x)=√3sin(wx-π/3),且f(x)的周期为8,求f(x)的单调增区间 函数f(x)=3sin(wx+ φ)对任意实数x都有f(π/3+x)=f(π/3-x)恒成立,设g(x)=3cos(wx+ φ)+1,则g(π/3)=___. 设函数f(x)=3sin(wx+圆周率/6),w>0,x属于R,且以圆周率/2为小正周期求f(x)解析式 设函数f(x)=3sin(wx+圆周率/6),w>0,x属于R,且以圆周率/2为小正周期求f(x)解析式 设函数f(x)=sin(wx+2π/3)+sin(wx-2π/3)（w＞0）的最小正周期为π,求函数的单调区间?