数列an满足a1=1 a2=3/2 an+2=3/2an+1-1/2an n属于正整数(n+2和n+1为角标)(1)记dn=an+1-an求证dn为等比数列(2)求数列an的通项公式(3)令bn=3n-2求数列{an*bn}的前n项和Sn
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