x+y+z=18 x-2y=0 x+2y+5z=35 解二元一次
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已知:x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值.
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方程组 (1) x+2y-3z=12 x-3y+2z= - 13 x-y-z=0 (2) x+ y=z 5x-y+z=18 2x+5y+3z= -1
解下列方程组x+y+z=18 x+y-z=0 x-2y+z=0
X+y+z=26,x-y=1,2x-y+z=18