将函数f(x)=2sin(2x+π/4)的图像向右平移fai（fai＞0）个单位,再将图像上每一点的横坐标缩短缩短1/2倍,所得图像关于直线x=π/4对称,则fai的最小正值为（）A.π /8 B.3π /8 C.3π /4 D.π /2为什么我算出来

函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域 将函数f(x)=sin(2x+θ)(-π/2 已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4) 已知函数f(x)=根号3sin2x+2sin(派/4+x)cos(派/4+x)将f(x)化为y=sin 将函数f(x)=sin(x/2)展开成x的幂级数 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 已知函数F(X)=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 函数f(x)=sin(2x+a) -π 设函数f(x)=sin(2x+ φ)(-π