数列an有a1=1,n>=2时,3tSn-(2t+3)S(n-1)=3t(常数a>0),问:求an的通项公式问题二若a(n+1)=an·f(t),bn=f(1/(n-1),求bn问题三求和b1b2-b2b3+b3b4-b4b5+…-b2n·b(2n+1)

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/18 14:01:22
xUnX~/M:I߀eJ.4&Q&iL`* @4fW:`(Vj# BsIm+V:wRtSOҴIÛPU&9Hdd qҏaӻ~aQro[Y wvAmTE}.Ue] ]&an^Wm&MlC {EW쟔|"8e_y[ӏ}t̿ZԤK)DQywжj_ç`r; yۼ9fp]ygG2'-eY7 =FHKjRD*)To"~f}!#i<I:*]'=͉5{y$z5GU g7tfs4>K6B oF~5lڬXD@ֱ#&'#KaiHAՂO[0f E{9ԍ3GՌ8߫"~okmv23FM.a*Vjgf,W4A7A ⰳ"eyXp.ǫ\ ŏ5 QE_ T;3kW 5XhMRt,VCOTVW4C%4hTx7߷1Ϳ2v`
1.设数列{an}的前n项和为Sn,其中an≠0,a1为常数,且-a1,Sn,an+1(n+1是a的下标啊,我打不出来)成等差数列,求{an}的通项公式2.数列{an}中,a1=1,Sn为其前n项的和,当t>0时,有3tSn-(2t+3)Sn-1=3t(n-1是S的下 数列an有a1=1,n>=2时,3tSn-(2t+3)S(n-1)=3t(常数a>0),问:求an的通项公式问题二若a(n+1)=an·f(t),bn=f(1/(n-1),求bn问题三求和b1b2-b2b3+b3b4-b4b5+…-b2n·b(2n+1) 数列{an}中,a1,=1,Sn为其前n项和,当t>0时,有3tSn-(2t+3) Sn-1 =3t(n∈N*,n≥2)(1) 求证:数列{an}是等比数列;(2)设数列{an}的公比为f(t),作数列{bn},使b1=1,bn=f( )(n∈N*,n≥2),求数 设数列(an)de 首项a1=1,前n项和Sn满足3tSn-(2t+3).Sn-1=3t(t>0,n=1,2,3,4,...)证明数列an是等比数列 设数列an的前n项和为Sn,Sn-tSn-1=n,a1=1(1)t=2,求a2,a3(2){an+1}是等比数列,求t的值(3)求sn 设数列an的首项a1=1,前n项和Sn=满足关系式tSn-(t+1)S(n-1)=t (t大于0,n属于N* n大于等于2) 求证:数列an是等比数列 证等比数列an:数列an前n项和Sn,满足a1=tSn-(2t+1)S(n-1)=t,t>0,n>=21,证数列an是等比数列. 数列an前n项和Sn,满足a1=tSn-(2t+1)S(n-1)=t,t>0,n>=21,证数列an是等比数列. 已知:数列{an}的首项a1=1,前n项和Sn满足 tSn-(t+1)Sn-1=t(t>0,≥2)求证:数列{an}是等比数列(n-1是角标) 设数列{an}的首项a1=1,前n项和Sn满足关系是:3tSn-(2t+3)S(n-1)=3t(t>0,n>=2)(1)求证:数列{an}是等比数列(2)设数列{an}的公比为f(t),作数列{bn},使b1=1,bn=f(1/b(n-1))(n>=2),求数列{bn}的 数列{an}的首项a1=1,前n项和Sn满足关系:3tSn-(2t+3)Sn-1=3t(t>0,n=2,3,4,5,).(1)数列{an}是等比数列(要有推理过程);(2)设数列{an}的公比为f(t),做数列{bn},使b1=1,bn=f(1/b(n-1))(n=2,3,4,…),求数列{ 设数列{An}的首项A1=1,前n项和Sn满足关系式:3tSn-(2t+3)Sn-1=3t(t>0,n为自然数n>=2) (1)求证:数列{An}是等比数列; (2)设数列{An}的公比为f(t),作数列{Bn},使B1=1,Bn=f{1/(bn-1)} (n为自然数,n>=2) 设数列{an}的前n项和为Sn,满足Sn-tSn-1=n(n大于等于2,n属于N),t为常数,且a1=1.(1)当t=2时,求a2和a3;(2)若{an +1}是等比数列,求t的值; 设数列{an}的首项a1=1,前n项和Sn满足关系:3tSn-(2t+3)Sn-1=3t(t>0,n=2,3,4,5,).求证:数列{an}是等比数列; 设数列{an}的首相a1=1,前n项和Sn满足关系式:3tSn-(2t+3)S(n-1)=3t(t>0,n=2,3,4,…)(1)求证数列{an}是等比数列(要有推理过程);(2)设数列{an}的公比为f(t),做数列{bn},使b1=1,bn=f(1/b(n-1 设数列{an}的首相a1=1,前n项和Sn满足关系式:3tSn-(2t+3)S(n-1)=3t(t>0,n=2,3,4,…)(1)求证数列{an}是等比数列(要有推理过程);(2)设数列{an}的公比为f(t),做数列{bn},使b1=1,bn=f(1/b(n-1 高手请帮我解答数列练习题设数列{an}a1=1,前N项的和Sn满足3tSn-(2t+3)Sn-1=3t(t〉0,n=2,3,4…)求证:(1) 数列{an}是等比数列(2) 设{an}公比为f(1/bn-1),作数列{bn}使b1=1,bn=f(1/bn-1)(n=2,3,4…) 数列{an}的首项a1=1,前n项和Sn满足关系:3tSn-(2t+3)Sn-1=3t(t>0,n=2,3,4,5,).求和:b1b2-b2b3+b3b4-b4b5+...+(-1)^n+1bnbn+1.(1)数列{an}是等比数列(要有推理过程);(2)设数列{an}的公比为f(t),做数列{bn},