log 1/2 {sin(π/3-πx/4)}的递增区间
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用C语言计算log(5)log(3)-log(2))/sin(π/3)=#include #includeint main(){int a=5,b=3,c=2;double y;y=(log(a)log(b)-log(c))/sin(π/b);printf((log(5)log(3)-log(2))/sin(π/3)=%ld,y);return 0;}x这哪里错了?
log 1/2 {sin(π/3-πx/4)}的递增区间
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