2cos(α-2π)=2cos(-2π+α)=2cosα2cos(α-2π)=-2cos(2π-α)=-2cosα那个是对的
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cos^2α+cos^2(α+π/3)-cosαcos(α+π/3)化简
Cos(α-π) Cos(α- π/2 )如何化简
计算:cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)
cos(π/17)*cos(2π/17)*cos(4π/17)*cos(8π/17)
为什么cos(θ-2π)=cosθ,
2sinα*cosα*cos(2π-α)+cos(π+2α)*cosα*tanα化简!
cos(-2/3)π=?
cos^2 π/8+cos ^2 3π/8+ cos^2 5π/8+cos^2 7π/8=?
[sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简
化简:cosα+cos(2π/3-α)+cos(2π/3+α)
【紧急求助】计算:cosα+cos(2π/3 +α)+cos(4π/3 +α)
求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
求值:cos(π/11)-cos(2π/11)+cos(3π/11)-cos(4π/11)+cos(5π/11)
cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
求证cosα^2+cos(α+β)^2-2cosαcosβcos(α+β)=sinβ^2
cos 2π/7 +cos 4π/7 +cos 6π/7=?
请问cos(2π/7)+cos(4π/7)+cos(6π/7)=?,
求和:cos(0)+cos(α)+cos(2α)+cos(3α)+……cos(nα)