设数列{an} {bn} 为 lim an bn = 0 判断命题 若an无界,则bn必有界.是否正确 为什么?
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设{an},{bn},{cn}均为非负数列,且lim(n->无穷)an=0,lim(n->无穷)bn=1lim(n->无穷)
设数列{an} {bn} 为 lim an bn = 0 判断命题 若an无界,则bn必有界.是否正确 为什么?
若lim(an/bn)=a(a不为0) lim(an)=0证明lim(bn)=0可考虑用数列极限的定义证明
已知数列{an}的前n项和为Sn,且a(n+1)=Sn-n+3,n∈N*,a1=2,设bn=3/(an-1),求lim(b1+b2+…+bn)
设 an 是无界数列 bn 是无穷大数列 证明 an bn 必为无界数列
设{an},{bn},{cn}均为非负数列,且lim(x→∝) an=0,lim(x→∝)bn=1设{an},{bn},{cn}均为非负数列,且lim(x→∝)an=0,lim(x→∝)bn=1,lim(x→∝)cn=∝,则必有(?)C、极限lim(x→∝)ancn不存在D、极限lim(x→
设数列{an}是等比数列,bn=an+an+1,问{bn}是否为等比数列
设各项均为正数的数列{an}和{bn}满足5^[an ],5^[bn] ,5^[a(n+1)] .设各项均为正数的数列{an}和{bn}满足5^[an ],5^[bn] ,5^[a(n+1)] 成等比数列,lg[bn],lg[a(n+1)],lg[bn+1]成等差数列,且a1=1,b1=2,a2=3,求通项an、bn.
{an}为数列设n—>无穷大时,lim an=a..请证明:(1) ,x—>无穷大时,lim[(a1+a2+…+an)/n]=a急
在数列an中,a1=1,a(n+1)=2an+2^n设bn=an/2^(n-1),bn为等差数列
a1=a,a2=r(r>0),且数列an*(an+1)是一个以q(q>0)为公比的等比数列.设bn=(a2n-1)+(a2n),Sn=b1+b2+b3+...bn,求bn及lim(1/Sn)
已知数列{an},{bn}满足a1=2,2an=1+2an*an+1,设{bn}=an-1求数列{1n}为等差数列急!!!
设数列{an}满足下列关系式a1=2a (a是不为0的常数)an =2a - a^2 / an-1 数列bn=1/(an-a)证明{bn}为等差数列
【高考】若数列{an}满足,a1=1,且a(n+1)=an/(1+an),设数列{bn}的前n项和为Sn,且Sn=2-bn,求{bn/an}的前...【高考】若数列{an}满足,a1=1,且a(n+1)=an/(1+an),设数列{bn}的前n项和为Sn,且Sn=2-bn,求{bn/an}的前n项和Tn
设各项均为正数的数列{an}和{bn}满足5^[an ],5^[bn] ,5^[a(n+1)] 成等比数列设各项均为正数的数列{an}和{bn}满足5^[an(n为下标)],5^[bn(n为下标)] ,5^[a(n+1)(n+1为下标)] 成等比数列,lg[bn(N为下标)],lg[a(n+1)(N+1
设数列An的前项合为Sn,已知a1=1S=4An+2设Bn=A-2An证明数列Bn是等比数列?求An的通项公式?
设数列{an}满足下列关系式a1=2a (a是不为0的常数)an =2a - a^2 / an-1 数列bn=1/(an-a),求{bn}都通项公式
设数列an的前n项和为Sn,满足an+sn=An^2+Bn+1(A不等于0)an为等差数列,求(B-1)/A