求y=-3sin(2x-π/3) x∈[-π,π]的单调递增区间
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/19 09:28:20
xPNP47?BX
id%E<K4R? wnUCe+v3g
已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos(x+y)+cos(x-y)】的值
sinx=1/3,sin(x+y)=1,求sin(2y+x)=?
y =(cos^2) x - sin (3^x),求y'
当cos^2x-cos^2y=√3/2时,求sin(x+y)×sin(x-y)
求y=-3sin(2x-π/3) x∈[-π,π]的单调递增区间
求y=sin(π/3-2x)+cos(π/3+2x)x∈R的最大值
求导数 y=sin^2(2x+π/3)
y=sin(x+π/3)+2定义域怎么求?
y=sin(2x-π/3) x∈(π/2,π)求值域
y=sin(2x+π/6),x∈[π/4,3π/4]求值域
求函数的值域y=sin(2x+π/3),x∈(-π/6,π)
求y=sin(2x+π/6)x∈(0,π/3)的值域
y=sin(3x-2) 求导数
求y=sin(2x+3)的导数
求函数y=3sin(2x+π/4),x∈R的周期
1.y=x*e^(2x) 2.y=(sin(2x))/x 3.y=sin(3x+(π/3))怎么求导数!
y=sin(x^2),求dy/d(x^3)
y=sin(x^3),求dy/d(x^2)