设α∈(0,π/3),β(π/6,π/2),且α,β满足5√3sinα+5cosα=8√2sinβ+√6cosβ =2 求cos(α+β )设α∈(0,π/3),β(π/6,π/2),且α,β满足53sinα+5cosα=8 /2sinβ+/6cosβ =2 求cos(α+β )

设α,β满足条件-π/2 设α,β满足条件-π/2 设-π/6 设3π/4 设-3π 设3π 设π/3 设π/2 1.设π/2 设π/2 设π/2 设5π/2 设-π/2 设π 设-π 设π 设π 设函数f(x)＝sin2x-cos(2x-π/6) 1.求[0,π/2]区间最大最小值 2.设α是设函数f(x)＝sin2x-cos(2x-π/6)1.求[0,π/2]区间最大最小值2.设α是锐角,f(α/2+π/4)=3/5求sinα