(1/x-1)+(2/6y-3)=1,(1/2x-2)-(1/2y-1)=0,解x、y.
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/25 17:47:46
xQN0~/!kYyћ`25@b$r%1^0aʸ+خx79ժ%qhF2aq*× -lEZg-2sцk2RFPqkg$B0
v#cj1SBԴlP%*@bu%͉ `CLO[uI4=o1_ףH@CC{5S͏eNܛ$O=ZafCqZ\-ǝMgi8[9jlɧPnE{Y]ȣG3
X|MaKE'SqrrymIin<
2(x+y)-3(x-y)=1 6(x+y)+(x-y)=51
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
已知:2x+y=6,x-3y=1 求7y(x-3y)(x-3y)-2(3y-x)(3y-x)
(x+y)(x-y)+(x-y)^2-(6x^2×y÷2y-2xy^2÷2y)其中x=-3,y=1/3
解二元一次方程组:3(x+y)-4(x-y)=4,x+y/2+x-y/6+1x+y/2+x-y/6+1=1
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
(x-2y)(x+y)-2x(-2x-3y)+6x(-x-y),其中x=-1,y=2
(x-2y)(x+y)-2x(-2x-3y)+6x(-x-y),其中x=-1,y=2要讲解和答题
{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
x-3y=1 x+2y=6
(3x-y)^2+(3x+y)(3x-y),x=1,y=-2
{6(x-y)-7(x+y)=21 {2(x-y)-5(x+y)=-1
二元一次方程 :2(x+y)-(x-y)=3 (x+y)-2(x-y)=1
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
变量x,y满足约束条件,x+y>=3,x-y>=-1,2x-y
(x-y)^2+(x+y)(x-y) 其中 X =3 Y=-1
x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2y,其中x=-2,y=1/3
(x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2Y,其中x=-2,y=1/3