直线x+y+2=0到直线xsina+ycosa+1=0(45°<a<90°)的角为?麻烦些清楚过程呃,答案是5π/4-a 请想清楚在回答
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![直线x+y+2=0到直线xsina+ycosa+1=0(45°<a<90°)的角为?麻烦些清楚过程呃,答案是5π/4-a 请想清楚在回答](/uploads/image/z/10030582-46-2.jpg?t=%E7%9B%B4%E7%BA%BFx%2By%2B2%3D0%E5%88%B0%E7%9B%B4%E7%BA%BFxsina%2Bycosa%2B1%3D0%EF%BC%8845%C2%B0%EF%BC%9Ca%EF%BC%9C90%C2%B0%EF%BC%89%E7%9A%84%E8%A7%92%E4%B8%BA%3F%E9%BA%BB%E7%83%A6%E4%BA%9B%E6%B8%85%E6%A5%9A%E8%BF%87%E7%A8%8B%E5%91%83%2C%E7%AD%94%E6%A1%88%E6%98%AF5%CF%80%2F4-a+%E8%AF%B7%E6%83%B3%E6%B8%85%E6%A5%9A%E5%9C%A8%E5%9B%9E%E7%AD%94)
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