设函数y=f(x)(x∈R且x≠0)对定义域内任意的x1x2恒有f(x1 * x2)=f(x1)+f(x2)1 求证 f(1)=f(-1)=02 求证y=f(x)是偶函数3 若f(x)为(0,+∞)上的增函数,解不等式f(x)+f(x-1/2)≤0
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/31 06:46:12
![设函数y=f(x)(x∈R且x≠0)对定义域内任意的x1x2恒有f(x1 * x2)=f(x1)+f(x2)1 求证 f(1)=f(-1)=02 求证y=f(x)是偶函数3 若f(x)为(0,+∞)上的增函数,解不等式f(x)+f(x-1/2)≤0](/uploads/image/z/10050387-51-7.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0y%3Df%EF%BC%88x%EF%BC%89%EF%BC%88x%E2%88%88R%E4%B8%94x%E2%89%A00%EF%BC%89%E5%AF%B9%E5%AE%9A%E4%B9%89%E5%9F%9F%E5%86%85%E4%BB%BB%E6%84%8F%E7%9A%84x1x2%E6%81%92%E6%9C%89f%EF%BC%88x1+%2A+x2%EF%BC%89%3Df%EF%BC%88x1%EF%BC%89%2Bf%EF%BC%88x2%EF%BC%891+%E6%B1%82%E8%AF%81+f%EF%BC%881%EF%BC%89%3Df%EF%BC%88-1%EF%BC%89%3D02+%E6%B1%82%E8%AF%81y%3Df%EF%BC%88x%EF%BC%89%E6%98%AF%E5%81%B6%E5%87%BD%E6%95%B03+%E8%8B%A5f%EF%BC%88x%EF%BC%89%E4%B8%BA%EF%BC%880%2C%2B%E2%88%9E%EF%BC%89%E4%B8%8A%E7%9A%84%E5%A2%9E%E5%87%BD%E6%95%B0%2C%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8Ff%EF%BC%88x%EF%BC%89%2Bf%EF%BC%88x-1%2F2%EF%BC%89%E2%89%A40)
xWOOG*K;;
CZ5R{XHӛiC"(6$VGI].&hg
}o$\77|m*J~ϝ|ĿFˤϚAOo'~?}n?䌇鳦dfdJUUHz` ԇxt&=stO`ճs =WPw:|aQJPgA=4]^7~ =עK/81ݗbiOnaap"x&~%P
Hw9xF]AWI(JW#/
Hް"FtCzZ7h5֓u~m/]MgP$7>Q&=*/)!;)ieSP9j4dDTqshB%t*\_ɑ,>܉=+3T,uGŠ~3m/.:
IH\;({>hW0
+^R
rvh_H9fZfLPPx-*hc?hԢCq<]ى!&VSy2$v/J-,-s$4!Af7cQF Bw\ݢ YtHr[
k;Y7M%Cw)h\[Re@b.e,O~[)?ܑY\&dG Dart^:N\(>&^t0\b6
?Y3VןsX5od2eT$ӜqM+X, ),@0YfJD\+n
݂'k,ћ L+-SAm
$\B6^~I
,qs Ll3)ĕeqũnuVd̼מs؎J@C7*ֿx!S6+dSVq