若定义域为R的二次函数f(x)的最小值为0,且有f(1+x)=f(1-x),直线g(x)=4(x-1)被f(x)的图像…截得的线段长为4根号17,则函数f(x)的解析式为?望各位帮帮忙~谢谢
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/18 21:30:47
![若定义域为R的二次函数f(x)的最小值为0,且有f(1+x)=f(1-x),直线g(x)=4(x-1)被f(x)的图像…截得的线段长为4根号17,则函数f(x)的解析式为?望各位帮帮忙~谢谢](/uploads/image/z/10065987-27-7.jpg?t=%E8%8B%A5%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BAR%E7%9A%84%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E4%B8%BA0%2C%E4%B8%94%E6%9C%89f%281%2Bx%29%3Df%281-x%29%2C%E7%9B%B4%E7%BA%BFg%28x%29%3D4%28x-1%29%E8%A2%ABf%28x%29%E7%9A%84%E5%9B%BE%E5%83%8F%E2%80%A6%E6%88%AA%E5%BE%97%E7%9A%84%E7%BA%BF%E6%AE%B5%E9%95%BF%E4%B8%BA4%E6%A0%B9%E5%8F%B717%2C%E5%88%99%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%E4%B8%BA%3F%E6%9C%9B%E5%90%84%E4%BD%8D%E5%B8%AE%E5%B8%AE%E5%BF%99%7E%E8%B0%A2%E8%B0%A2)
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