抽象函数.为什么说f(x+y)=f(x)+(y)就相当于y=kx(正比例函数呢)?还有如果变形了呢.f(xy)=f(x)f(y)-----y=x的n次方(指数函数)f(xy)=f(x)+f(y)-----y=以a为底的x的对数(对数函数)f(x+y)=f(x)f(y)-----y=a的x次
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![抽象函数.为什么说f(x+y)=f(x)+(y)就相当于y=kx(正比例函数呢)?还有如果变形了呢.f(xy)=f(x)f(y)-----y=x的n次方(指数函数)f(xy)=f(x)+f(y)-----y=以a为底的x的对数(对数函数)f(x+y)=f(x)f(y)-----y=a的x次](/uploads/image/z/10113413-5-3.jpg?t=%E6%8A%BD%E8%B1%A1%E5%87%BD%E6%95%B0.%E4%B8%BA%E4%BB%80%E4%B9%88%E8%AF%B4f%28x%2By%29%3Df%28x%29%2B%28y%29%E5%B0%B1%E7%9B%B8%E5%BD%93%E4%BA%8Ey%3Dkx%EF%BC%88%E6%AD%A3%E6%AF%94%E4%BE%8B%E5%87%BD%E6%95%B0%E5%91%A2%EF%BC%89%3F%E8%BF%98%E6%9C%89%E5%A6%82%E6%9E%9C%E5%8F%98%E5%BD%A2%E4%BA%86%E5%91%A2.f%28xy%29%3Df%28x%29f%28y%29-----y%3Dx%E7%9A%84n%E6%AC%A1%E6%96%B9%EF%BC%88%E6%8C%87%E6%95%B0%E5%87%BD%E6%95%B0%EF%BC%89f%28xy%29%3Df%28x%29%2Bf%28y%29-----y%3D%E4%BB%A5a%E4%B8%BA%E5%BA%95%E7%9A%84x%E7%9A%84%E5%AF%B9%E6%95%B0%EF%BC%88%E5%AF%B9%E6%95%B0%E5%87%BD%E6%95%B0%EF%BC%89f%28x%2By%29%3Df%28x%29f%28y%29-----y%3Da%E7%9A%84x%E6%AC%A1)
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