函数y=log(1/3)[sin(π/4-π/3)]的单调递增区间是( ),求详解,

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/03 05:30:10
函数y=log(1/3)[sin(π/4-π/3)]的单调递增区间是( ),求详解,
x){ھ 9ƚřyMtfY-O{aEz9}˳54umlz~ًule~ U&^.|';zy~; }:/xg _z?e{~qAbUQ

函数y=log(1/3)[sin(π/4-π/3)]的单调递增区间是( ),求详解,
函数y=log(1/3)[sin(π/4-π/3)]的单调递增区间是( ),求详解,

函数y=log(1/3)[sin(π/4-π/3)]的单调递增区间是( ),求详解,

题目不全,请核对题目后追问.(缺少自变量x)