求这四道题的答案(二次根式)
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求这四道题的答案(二次根式)
求这四道题的答案(二次根式)
求这四道题的答案(二次根式)
(27/5)√[(13²-12²)/27]
=(27/5)√[(13+12)(13-12)/27]
=(27/5)√(25/27)
=(27/5)√[(5/9)²×3]
=(27/5×5/9)√3
=3√3
(-abc/2)√[c³/(2a^4b)]
=(-abc/2)√{ [c/(2a²b)]²×2bc }
=(-abc/2)×c/(2a²b)×√(2bc)
=[-c²/(4a)]√(2bc)
5√(ab)×[-4√(a³b)] (a≥0,b≥0)
=5×(-4)×√(ab×a³b)
=-20×√(a^4b²)
=-20×√(a²b)²
=-20a²b
√(a³b^6)÷√(ab) (a﹥0,b﹥0)
=√(a³b^6÷ab)
=√(a²b^5)
=√[(ab²)²×b]
=ab²√b