tan兀/12一1/tan兀/12
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tan兀/12一1/tan兀/12
tan兀/12一1/tan兀/12
tan兀/12一1/tan兀/12
tan(π/12)一1/tan(π/12)=4
tan兀/12一1/tan兀/12
tan(π/12)-(1/tan(π/12))
tan(兀/2-A)=1/tan
(1-tan^2π/12)/(tanπ/12)化简
计算 tanπ/12+1/tanπ/12
计算tanπ/12 / (1-tan^2π/12)=
求tan 派/12-1/tan派/12的值
tan(π/12)+1/tan(π/12)=啥?
tanπ/12-1/tanπ/12=
化简:tan(π/8)+1/tan(π/12)
tan(π/8)+1/(tan(π/12))值,要过程
化简:[tan(5/4)π+tan(5/12)π]/[1-tan(5/12)π]
化简:[tan(5π)/4+tan(5π)/12]/[1-tan(5π)/12]
【tan(5pai/4)+tan(5pai/12)】/【1-tan(5pai/12)】如何化简
tan(-17兀/6) .
tan(-17兀/6)
tan派/12
化简tan(18-x)tan(12+x)+根号3[tan(18-x)+tan(12+x)]