如图,△ABC为等边三角形,D为BC上任意一点,∠ADE=60°,边DE与△ABC的外角∠ACF的平分线交于点E.求证:AD=DE
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![如图,△ABC为等边三角形,D为BC上任意一点,∠ADE=60°,边DE与△ABC的外角∠ACF的平分线交于点E.求证:AD=DE](/uploads/image/z/10156943-47-3.jpg?t=%E5%A6%82%E5%9B%BE%2C%E2%96%B3ABC%E4%B8%BA%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2%2CD%E4%B8%BABC%E4%B8%8A%E4%BB%BB%E6%84%8F%E4%B8%80%E7%82%B9%2C%E2%88%A0ADE%3D60%C2%B0%2C%E8%BE%B9DE%E4%B8%8E%E2%96%B3ABC%E7%9A%84%E5%A4%96%E8%A7%92%E2%88%A0ACF%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%E4%BA%A4%E4%BA%8E%E7%82%B9E.%E6%B1%82%E8%AF%81%EF%BC%9AAD%3DDE)
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