sin(n*π/2)*sin(n*π/3)*sin(n*π/4)*...*sin(n*π/n-1) 求化简成一个关于n的表达式,
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![sin(n*π/2)*sin(n*π/3)*sin(n*π/4)*...*sin(n*π/n-1) 求化简成一个关于n的表达式,](/uploads/image/z/10158252-60-2.jpg?t=sin%28n%2A%CF%80%2F2%29%2Asin%28n%2A%CF%80%2F3%29%2Asin%28n%2A%CF%80%2F4%29%2A...%2Asin%28n%2A%CF%80%2Fn-1%29+%E6%B1%82%E5%8C%96%E7%AE%80%E6%88%90%E4%B8%80%E4%B8%AA%E5%85%B3%E4%BA%8En%E7%9A%84%E8%A1%A8%E8%BE%BE%E5%BC%8F%2C)
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sin(n*π/2)*sin(n*π/3)*sin(n*π/4)*...*sin(n*π/n-1) 求化简成一个关于n的表达式,
sin(n*π/2)*sin(n*π/3)*sin(n*π/4)*...*sin(n*π/n-1) 求化简成一个关于n的表达式,
sin(n*π/2)*sin(n*π/3)*sin(n*π/4)*...*sin(n*π/n-1) 求化简成一个关于n的表达式,
真没有公式,只能说n是合数时其值为0,n是素数是非0,但没法看出规律
n较大时数值非常接近0
sin(n*π/2)*sin(n*π/3)*sin(n*π/4)*...*sin(n*π/n-1) 求化简成一个关于n的表达式,
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