f(x)=xe^x+ax^2+bx 在x=0和x=-1时都取得极值1.求a和b的值2.若存在实数x属于〔1,2〕,使得不等式f(x)《二分之一x^2+(t-1)x成立,求实数t的取值范围;一楼解错了 二楼第一个问对了下面的不详细
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![f(x)=xe^x+ax^2+bx 在x=0和x=-1时都取得极值1.求a和b的值2.若存在实数x属于〔1,2〕,使得不等式f(x)《二分之一x^2+(t-1)x成立,求实数t的取值范围;一楼解错了 二楼第一个问对了下面的不详细](/uploads/image/z/10171686-30-6.jpg?t=f%EF%BC%88x%EF%BC%89%3Dxe%5Ex%2Bax%5E2%2Bbx+%E5%9C%A8x%3D0%E5%92%8Cx%3D-1%E6%97%B6%E9%83%BD%E5%8F%96%E5%BE%97%E6%9E%81%E5%80%BC1.%E6%B1%82a%E5%92%8Cb%E7%9A%84%E5%80%BC2.%E8%8B%A5%E5%AD%98%E5%9C%A8%E5%AE%9E%E6%95%B0x%E5%B1%9E%E4%BA%8E%E3%80%941%2C2%E3%80%95%2C%E4%BD%BF%E5%BE%97%E4%B8%8D%E7%AD%89%E5%BC%8Ff%EF%BC%88x%EF%BC%89%E3%80%8A%E4%BA%8C%E5%88%86%E4%B9%8B%E4%B8%80x%5E2%2B%EF%BC%88t-1%EF%BC%89x%E6%88%90%E7%AB%8B%2C%E6%B1%82%E5%AE%9E%E6%95%B0t%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%EF%BC%9B%E4%B8%80%E6%A5%BC%E8%A7%A3%E9%94%99%E4%BA%86+%E4%BA%8C%E6%A5%BC%E7%AC%AC%E4%B8%80%E4%B8%AA%E9%97%AE%E5%AF%B9%E4%BA%86%E4%B8%8B%E9%9D%A2%E7%9A%84%E4%B8%8D%E8%AF%A6%E7%BB%86)
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