化简sin(π/3+α)+sin(π/3-α)如题

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化简sin(π/3+α)+sin(π/3-α)如题
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化简sin(π/3+α)+sin(π/3-α)如题
化简sin(π/3+α)+sin(π/3-α)
如题

化简sin(π/3+α)+sin(π/3-α)如题
这个可以用和差化积的,只不过要先用诱导公式变一下：
比如说都变成sin的
原式=sin(π/6-α)+sin(π/6+α）
=2sin0.5*[(π/6-α)+(π/6+α)] cos0.5[(π/6-α)-(π/6+α)]
=2sin π/6 cosα
=cosα

罪（π/ 2 +α）+ COS（π/ 3 +α）
= COS（π/2-π/2-α）+cosπ/ 3COSα-sinπ/ 3sinα
=COSα +1 / 2COSα-√3/2sinsα
= 3/2COSα-√3/2sinsα
=√3（√3/2cosα-1/2sinα）
=√ 3（cosπ/ 6COSα-sinπ/ 6sinα）
=√3cos（π/ 6 +α）
（角差角公式的利用和转化）

化简sin(α+β)+sin(α-β)+2sinαsin(3π/2-β)= 化简：sin²α+sin²（α+π/3）+sin²（α-π/3） sin(π/3-α)如何等于sin(π/3+α) 2sin(α+π/3）=sinα+______ sin(α-3π)等于 化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α) 化简:[sin(2004π-α)cos(α-2005π)/cot(2003π-α)sin(α+3π)]+sin(α-π) 化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α) 已知sin(3π-α)=-2sin(π/2+α)则sinαcosα 求sin^2α+sin^2(π/3 +α)+sin^2(π/3 -α) 化简 sin²x+sin²(x+2π/3)+sin²(x-2π/3) 化简sin^2A+sin^(A-π/3)+sin(A+π/3) 化简：sin方A+sin方(A-π/3)+sin方(A+π/3) 化简；sin^2 A+sin^2(A-π/3)+sin^2(A+π/3) 化简 sin(π+α)+sin(2π+α)+sin(3π+α)+……+sin(kπ+α) k属于Z 化简:(sinα-cosα)^2+sin4α/2cos2α 化简:sin^2x+sin^2(x+2π/3)+sin^2(x-2π/3) sin(-π/3) 计算,sin(π/12)-sin(5π/12)+2sin(π/8)sin(3π/8)