求值域y=(1-e的x次方)/(1+e的x次方)e不确定正负 怎么算?

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求值域y=(1-e的x次方)/(1+e的x次方)e不确定正负 怎么算?
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求值域y=(1-e的x次方)/(1+e的x次方)e不确定正负 怎么算?
求值域y=(1-e的x次方)/(1+e的x次方)
e不确定正负 怎么算?

求值域y=(1-e的x次方)/(1+e的x次方)e不确定正负 怎么算?
设e^x=t 则t>0
y=(1-t)/(1+t)
=(-1-t+2)/(1+t)
=-1+2/(1+t)
1+t>1
所以0<2/(1+t)<2
-1

e为自然对数,2.7多
http://baike.baidu.com/view/11033.htm