y=(x∧2－2x＋2)/x x∈(0,1/4】的取值范围

x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 求y=(x^2)+2x(x≥0) y=-x+2x(x y=(x∧2－2x＋2)/x x∈(0,1/4】的取值范围 Y=X^2X (X>0) 求导Y=X^2X (X>0) 求d(Y)/d(X) 因式分解x(x+y)(x-y)-x(x+y)^2 y=x^2-2x（x y=x^2+2x(x 3^x+2x=y,x y=x^2-2x (x≥0) -x^2-2x(x 把6x（x－y）的平方＋3（y－x）的立方分解因式我知道答案是6x(x-y)^2+3(y-x)^3=6x(x-y)^2-3(x-y)^3=3(x-y)^2[2x-(x-y)]=3(x-y)^2(x+y)可为什么=6x(x-y)^2-3(x-y)^3=3(x-y)^2[2x-(x-y)] 变量x,y满足x-2y=0,x mathematica软件,已知y[x],Y=f1(x),X(x)=f2(x),如何plot Y[X]?y[x_] := x + 9.81/2*x*xk=1X[x] = x - k*y'[x]/(1 + (y'[x])^2)^0.5Y[x] = y[x] + k/(1 + (y'[x])^2)^0.5Plot[{y[x],Y[X],},{x,0,2}] 3x(2x＋y)－2x(x-y),其中x＝1,y=1/5 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 假设集合U={(x,y)|x∈R,y∈R },A={(x,y)|2x-y+m>0},B={(x,y)|x+y-n y=1-x^2 x>=0 ,y=sin|x|/x x 先化简,再求值 [2/3x - 2/x+y（x+y/3x -x-y）]*x/x-y,其中5x+3y=0 已知x>0,Y>0,如何证x^2/y+y^2/x>=x+y