b(n+1)=b(n)^2+b(n)如何求该递推公式的通项公式b(1)=1/3,麻烦一定要写上步骤与求法其实原问题是求T(n)=1/(b(1)+1)+1/(b(2)+1)+1/(b(3)+1)+……+1/(b(n)+1)>(3m-1)/12对任意n不小于2且m为正整数恒成立,求m的最大
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![b(n+1)=b(n)^2+b(n)如何求该递推公式的通项公式b(1)=1/3,麻烦一定要写上步骤与求法其实原问题是求T(n)=1/(b(1)+1)+1/(b(2)+1)+1/(b(3)+1)+……+1/(b(n)+1)>(3m-1)/12对任意n不小于2且m为正整数恒成立,求m的最大](/uploads/image/z/10220048-8-8.jpg?t=b%28n%2B1%29%3Db%28n%29%5E2%2Bb%28n%29%E5%A6%82%E4%BD%95%E6%B1%82%E8%AF%A5%E9%80%92%E6%8E%A8%E5%85%AC%E5%BC%8F%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8Fb%281%29%3D1%2F3%2C%E9%BA%BB%E7%83%A6%E4%B8%80%E5%AE%9A%E8%A6%81%E5%86%99%E4%B8%8A%E6%AD%A5%E9%AA%A4%E4%B8%8E%E6%B1%82%E6%B3%95%E5%85%B6%E5%AE%9E%E5%8E%9F%E9%97%AE%E9%A2%98%E6%98%AF%E6%B1%82T%28n%29%3D1%2F%28b%281%29%2B1%29%2B1%2F%28b%282%29%2B1%29%2B1%2F%28b%283%29%2B1%29%2B%E2%80%A6%E2%80%A6%2B1%2F%28b%28n%29%2B1%29%3E%283m-1%29%2F12%E5%AF%B9%E4%BB%BB%E6%84%8Fn%E4%B8%8D%E5%B0%8F%E4%BA%8E2%E4%B8%94m%E4%B8%BA%E6%AD%A3%E6%95%B4%E6%95%B0%E6%81%92%E6%88%90%E7%AB%8B%EF%BC%8C%E6%B1%82m%E7%9A%84%E6%9C%80%E5%A4%A7)
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