liuking123进来 f(X+C)=-F(X)函数周期性(注意有-号的) f(X+C)=-f(X) 设x+c=t,x=t-c f(t)=-f(t-c) 就是f(x)=-f(x-c) 这以上我懂 f(X+C)=-f(X) f(x-c)=f[(x+c)-2c] 这个是怎么变换来的,我基础比较差 下面我懂 就是f(x
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![liuking123进来 f(X+C)=-F(X)函数周期性(注意有-号的) f(X+C)=-f(X) 设x+c=t,x=t-c f(t)=-f(t-c) 就是f(x)=-f(x-c) 这以上我懂 f(X+C)=-f(X) f(x-c)=f[(x+c)-2c] 这个是怎么变换来的,我基础比较差 下面我懂 就是f(x](/uploads/image/z/10331129-65-9.jpg?t=liuking123%E8%BF%9B%E6%9D%A5+f%EF%BC%88X%2BC%29%3D-F%28X%29%E5%87%BD%E6%95%B0%E5%91%A8%E6%9C%9F%E6%80%A7%EF%BC%88%E6%B3%A8%E6%84%8F%E6%9C%89-%E5%8F%B7%E7%9A%84%EF%BC%89+f%EF%BC%88X%2BC%29%3D-f%28X%29+%E8%AE%BEx%2Bc%3Dt%2Cx%3Dt-c+f%28t%29%3D-f%28t-c%29+%E5%B0%B1%E6%98%AFf%28x%29%3D-f%28x-c%29+%E8%BF%99%E4%BB%A5%E4%B8%8A%E6%88%91%E6%87%82+f%EF%BC%88X%2BC%29%3D-f%28X%29+f%28x-c%29%3Df%5B%28x%2Bc%29-2c%5D+%E8%BF%99%E4%B8%AA%E6%98%AF%E6%80%8E%E4%B9%88%E5%8F%98%E6%8D%A2%E6%9D%A5%E7%9A%84%2C%E6%88%91%E5%9F%BA%E7%A1%80%E6%AF%94%E8%BE%83%E5%B7%AE+%E4%B8%8B%E9%9D%A2%E6%88%91%E6%87%82+%E5%B0%B1%E6%98%AFf%28x)
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