已知正项数列an的首项a1=m,其中0<m<1函数f(x)=x/1+x若正项数列an满足an+1=f(an) (n≧1且n∈N) 证1/an 为等差数列,并求出an的通项公式?若an满足an+1≦f(an) (n≧1且n∈N) 数列bn满足 bn=an/n+1,试证:
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![已知正项数列an的首项a1=m,其中0<m<1函数f(x)=x/1+x若正项数列an满足an+1=f(an) (n≧1且n∈N) 证1/an 为等差数列,并求出an的通项公式?若an满足an+1≦f(an) (n≧1且n∈N) 数列bn满足 bn=an/n+1,试证:](/uploads/image/z/10341101-29-1.jpg?t=%E5%B7%B2%E7%9F%A5%E6%AD%A3%E9%A1%B9%E6%95%B0%E5%88%97an%E7%9A%84%E9%A6%96%E9%A1%B9a1%3Dm%2C%E5%85%B6%E4%B8%AD0%EF%BC%9Cm%EF%BC%9C1%E5%87%BD%E6%95%B0f%28x%29%3Dx%EF%BC%8F1%EF%BC%8Bx%E8%8B%A5%E6%AD%A3%E9%A1%B9%E6%95%B0%E5%88%97an%E6%BB%A1%E8%B6%B3an%EF%BC%8B1%3Df%28an%29+%28n%E2%89%A71%E4%B8%94n%E2%88%88N%29+%E8%AF%811%EF%BC%8Fan+%E4%B8%BA%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%2C%E5%B9%B6%E6%B1%82%E5%87%BAan%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%3F%E8%8B%A5an%E6%BB%A1%E8%B6%B3an%2B1%E2%89%A6f%28an%29+%28n%E2%89%A71%E4%B8%94n%E2%88%88N%29+%E6%95%B0%E5%88%97bn%E6%BB%A1%E8%B6%B3+bn%3Dan%EF%BC%8Fn%2B1%2C%E8%AF%95%E8%AF%81%EF%BC%9A)
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