一道三角形数学题,不同解法,竟有不同答案,哪里错了?一直角三角形有一锐角为30°,ac长2cm,求斜边ab的长.解法一:设bc为x,则2^2+x^2=(2x)^24+x^2=4x^24+x^2-4x^2=0-3x^2=-4x^2=4/3x=±2√▔3/3解法二:设ac为x,则
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![一道三角形数学题,不同解法,竟有不同答案,哪里错了?一直角三角形有一锐角为30°,ac长2cm,求斜边ab的长.解法一:设bc为x,则2^2+x^2=(2x)^24+x^2=4x^24+x^2-4x^2=0-3x^2=-4x^2=4/3x=±2√▔3/3解法二:设ac为x,则](/uploads/image/z/10353805-61-5.jpg?t=%E4%B8%80%E9%81%93%E4%B8%89%E8%A7%92%E5%BD%A2%E6%95%B0%E5%AD%A6%E9%A2%98%2C%E4%B8%8D%E5%90%8C%E8%A7%A3%E6%B3%95%2C%E7%AB%9F%E6%9C%89%E4%B8%8D%E5%90%8C%E7%AD%94%E6%A1%88%2C%E5%93%AA%E9%87%8C%E9%94%99%E4%BA%86%3F%E4%B8%80%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2%E6%9C%89%E4%B8%80%E9%94%90%E8%A7%92%E4%B8%BA30%C2%B0%2Cac%E9%95%BF2cm%2C%E6%B1%82%E6%96%9C%E8%BE%B9ab%E7%9A%84%E9%95%BF.%E8%A7%A3%E6%B3%95%E4%B8%80%EF%BC%9A%E8%AE%BEbc%E4%B8%BAx%2C%E5%88%992%5E2%2Bx%5E2%3D%282x%29%5E24%2Bx%5E2%3D4x%5E24%2Bx%5E2-4x%5E2%3D0-3x%5E2%3D-4x%5E2%3D4%2F3x%3D%C2%B12%E2%88%9A%E2%96%943%2F3%E8%A7%A3%E6%B3%95%E4%BA%8C%EF%BC%9A%E8%AE%BEac%E4%B8%BAx%2C%E5%88%99)
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