sin²a+cosacos(π/3+a)-sin²(π/6-a)=cos²80°+sin²50°-sin190°·cos320°=tana=√3(1+m),tan(-β)=√3(tanatanβ+m),又a,β都是钝角,a+β=过程当然要啦~3Q
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![sin²a+cosacos(π/3+a)-sin²(π/6-a)=cos²80°+sin²50°-sin190°·cos320°=tana=√3(1+m),tan(-β)=√3(tanatanβ+m),又a,β都是钝角,a+β=过程当然要啦~3Q](/uploads/image/z/10394051-59-1.jpg?t=sin%26sup2%3Ba%2Bcosacos%28%CF%80%2F3%2Ba%29-sin%26sup2%3B%28%CF%80%2F6-a%29%3Dcos%26sup2%3B80%C2%B0%2Bsin%26sup2%3B50%C2%B0-sin190%C2%B0%C2%B7cos320%C2%B0%3Dtana%3D%E2%88%9A3%281%2Bm%29%2Ctan%28-%CE%B2%29%3D%E2%88%9A3%28tanatan%CE%B2%2Bm%29%2C%E5%8F%88a%2C%CE%B2%E9%83%BD%E6%98%AF%E9%92%9D%E8%A7%92%2Ca%2B%CE%B2%3D%E8%BF%87%E7%A8%8B%E5%BD%93%E7%84%B6%E8%A6%81%E5%95%A6%7E3Q)
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sin²a+cosacos(π/3+a)-sin²(π/6-a)=cos²80°+sin²50°-sin190°·cos320°=tana=√3(1+m),tan(-β)=√3(tanatanβ+m),又a,β都是钝角,a+β=过程当然要啦~3Q
sin²a+cosacos(π/3+a)-sin²(π/6-a)=
cos²80°+sin²50°-sin190°·cos320°=
tana=√3(1+m),tan(-β)=√3(tanatanβ+m),又a,β都是钝角,a+β=
过程当然要啦~3Q
sin²a+cosacos(π/3+a)-sin²(π/6-a)=cos²80°+sin²50°-sin190°·cos320°=tana=√3(1+m),tan(-β)=√3(tanatanβ+m),又a,β都是钝角,a+β=过程当然要啦~3Q
1、1/4
2、3/4
3、240°(或写成(4/3)π)
需要具体过程的话,说一声,我再往上传.
A
abc
化简 sin^2a+cosacos(π/3+a)-sin^2(π/6-a)帮个小忙啊.
sin²a+cosacos(π/3+a)-sin²(π/6-a)=cos²80°+sin²50°-sin190°·cos320°=tana=√3(1+m),tan(-β)=√3(tanatanβ+m),又a,β都是钝角,a+β=过程当然要啦~3Q
cosacos分之sin(a+b)=tana+tanb
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