设f(x+y,xy)=x^2+y^2-xy,则(∂f(x,y))/∂y=
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设f(x+y,xy)=x^2+y^2-xy,则(∂f(x,y))/∂y=
设f(x+y,xy)=x^2+y^2-xy,则(∂f(x,y))/∂y=
设f(x+y,xy)=x^2+y^2-xy,则(∂f(x,y))/∂y=
f(x+y,xy)=x^2+y^2-xy
=(x+y)^2-3xy
f(x,y)=x^2-3y
(∂f(x,y))/∂y= -3
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