设函数f(x)=sinx+cosx和g(x)=2sinxcosx试求F(x)=f(x)+ag(x)在[0,0.5π]上的最小值h(a)若设函数f(x)=sinx+cosx和g(x)=2sinxcosx(1)试求F(x)=f(x)+ag(x)在[0,0.5π]上的最小值h(a)(2)若存在x0∈[0,π/2],使|af(x)-g(x)-3|≥1/2成
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![设函数f(x)=sinx+cosx和g(x)=2sinxcosx试求F(x)=f(x)+ag(x)在[0,0.5π]上的最小值h(a)若设函数f(x)=sinx+cosx和g(x)=2sinxcosx(1)试求F(x)=f(x)+ag(x)在[0,0.5π]上的最小值h(a)(2)若存在x0∈[0,π/2],使|af(x)-g(x)-3|≥1/2成](/uploads/image/z/1043345-65-5.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%3Dsinx%2Bcosx%E5%92%8Cg%28x%29%3D2sinxcosx%E8%AF%95%E6%B1%82F%28x%29%3Df%28x%29%2Bag%28x%29%E5%9C%A8%5B0%2C0.5%CF%80%5D%E4%B8%8A%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BCh%28a%29%E8%8B%A5%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%3Dsinx%2Bcosx%E5%92%8Cg%28x%29%3D2sinxcosx%EF%BC%881%EF%BC%89%E8%AF%95%E6%B1%82F%28x%29%3Df%28x%29%2Bag%28x%29%E5%9C%A8%5B0%2C0.5%CF%80%5D%E4%B8%8A%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BCh%28a%29%EF%BC%882%EF%BC%89%E8%8B%A5%E5%AD%98%E5%9C%A8x0%E2%88%88%5B0%2C%CF%80%2F2%5D%2C%E4%BD%BF%7Caf%28x%29-g%28x%29-3%7C%E2%89%A51%2F2%E6%88%90)
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