已知二次函数f(x)=x^2-ax+a(a>0,x属于R)有且只有一个零点,数列an的前n项和Sn=f(n)(n属于正整数)⑴求数列an的通项公式⑵设Bn=an/3^n,求数列Bn的前n项和Tn
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![已知二次函数f(x)=x^2-ax+a(a>0,x属于R)有且只有一个零点,数列an的前n项和Sn=f(n)(n属于正整数)⑴求数列an的通项公式⑵设Bn=an/3^n,求数列Bn的前n项和Tn](/uploads/image/z/1071646-70-6.jpg?t=%E5%B7%B2%E7%9F%A5%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dx%5E2-ax%2Ba%EF%BC%88a%EF%BC%9E0%2Cx%E5%B1%9E%E4%BA%8ER%EF%BC%89%E6%9C%89%E4%B8%94%E5%8F%AA%E6%9C%89%E4%B8%80%E4%B8%AA%E9%9B%B6%E7%82%B9%2C%E6%95%B0%E5%88%97an%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8CSn%3Df%EF%BC%88n%EF%BC%89%EF%BC%88n%E5%B1%9E%E4%BA%8E%E6%AD%A3%E6%95%B4%E6%95%B0%EF%BC%89%E2%91%B4%E6%B1%82%E6%95%B0%E5%88%97an%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%E2%91%B5%E8%AE%BEBn%3Dan%2F3%5En%2C%E6%B1%82%E6%95%B0%E5%88%97Bn%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8CTn)
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