lim (2n-1)/(2^n)=?n=>无穷大

lim(1-1/n)^(n^2)=? lim(1-1/n^2)^n=? lim (2n-1)/(2^n)=?n=>无穷大 lim根号n^2+n+1/3n-2=? lim n->∞{2/((1+ 1/n )^n)}=? lim(3^2n+5^n)/(1+9^n)=? lim[(4+7+...+3n+1)/(n^2-n)]= lim n--∞ (1+2/n)^n=?如题 lim(1/n+2/n+3/n+4/n+5/n+……+n/n)=lim(1/n)+lim(2/n)+……+lim(n/n)成立吗?（n趋近于无穷大）为什么不成立? 高数题：n趋近于0,lim｛1/（n^2+n+1)+2/(n^2+n+2)+3/(n^2+n+3)+.+n/(n^2+n+n)｝=? lim(n+2)(n-1)/3n^2+2n+1= n趋近于无穷 lim[1+(1/n)]^n=e,则lim[(n+1)/n]^(2n+1)的值等于?e^2 lim[1+(1/n)]^n=e,则lim[n+(1/n)]^(2n+1)的值等于?e^2 求极限 lim(n→∞) tan^n (π/4 + 2/n) lim(n→∞)tan^n(π/4+2/n) =lim(n→∞)[(tan(π/4)+tan(2/n))/(1-tan(π/4)tan(2/n))]^n =lim(n→∞)[(1+tan(2/n))/(1-tan(2/n))]^n =lim(n→∞)(1+tan(2/n))^n/(1-tan(2/n))^n (1) 因为 lim(n→∞)(1+tan(2/n) 求极限,lim(1+n)(1+n^2)(1+n^4)-----(1+n^2n)=?（n趋于无穷） 大一微积分解答：lim(n→+∞)（2^n+4^n+6^n+8^n）^1/n=? lim(n→∞) (1/n)[sin(π/n)+sin(2π/n)+…+sin(nπ/n)]=? lim(n^2+1)/n(2n-1),n趋于正无穷lim(n^2+1)/n(2n-1)=？