数列{an}的前n项和记为Sn,且a1=1/2,an=2S(n-1)+1,(n大于等于2) (1)求数列{an}的通项公式 (2)设bn=an+n,记数列{bn}的前n项和为Tn,当n大于等于2时,求Tn的表达式
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![数列{an}的前n项和记为Sn,且a1=1/2,an=2S(n-1)+1,(n大于等于2) (1)求数列{an}的通项公式 (2)设bn=an+n,记数列{bn}的前n项和为Tn,当n大于等于2时,求Tn的表达式](/uploads/image/z/10773093-21-3.jpg?t=%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E8%AE%B0%E4%B8%BASn%2C%E4%B8%94a1%3D1%2F2%2Can%3D2S%28n-1%29%2B1%2C%28n%E5%A4%A7%E4%BA%8E%E7%AD%89%E4%BA%8E2%29+%281%29%E6%B1%82%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F+%282%29%E8%AE%BEbn%3Dan%2Bn%2C%E8%AE%B0%E6%95%B0%E5%88%97%7Bbn%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BATn%2C%E5%BD%93n%E5%A4%A7%E4%BA%8E%E7%AD%89%E4%BA%8E2%E6%97%B6%2C%E6%B1%82Tn%E7%9A%84%E8%A1%A8%E8%BE%BE%E5%BC%8F)
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