求解齐性方程组X1-8X2+10X3+2X4=0,2X1+4X2+5X3-X4=0,3X1+8X2+6X3-2X4=0的基础解系与通解
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求解齐性方程组X1-8X2+10X3+2X4=0,2X1+4X2+5X3-X4=0,3X1+8X2+6X3-2X4=0的基础解系与通解
求解齐性方程组X1-8X2+10X3+2X4=0,2X1+4X2+5X3-X4=0,3X1+8X2+6X3-2X4=0的基础解系与通解
求解齐性方程组X1-8X2+10X3+2X4=0,2X1+4X2+5X3-X4=0,3X1+8X2+6X3-2X4=0的基础解系与通解
基础解系有两个a1=(-4,3/4,1,0)和a2=(0,1/4,0,1)
通解为c1a1+c2a2
求解齐性方程组X1-8X2+10X3+2X4=0,2X1+4X2+5X3-X4=0,3X1+8X2+6X3-2X4=0的基础解系与通解
Mathematica求解线性规划8x1+2x2+10x3
用逆矩阵求解下列方程组X1+2X2+3X3=12X1+2X2+5X3=23X1+5X2+X3=3
MATLAB用初等行变换法求解方程组x1+x2-3x3= -32x1+x2-4x3= -5x1+2x2-5x3= -4
齐次线性方程求解:X1-X2+5X3-X4=0X1+X2-2X3+3X4=03X1-X2+8X3+X4=0X1+3X2-9X3+7X4=0
求解下列非齐次线性方程组|4x1+2x2-x3=2|3x1-x2+2x3=10|11x1+3x2=8
求解线性方程组的一般解方程组为 x1-x2+x4=2x1-2x2+x3+4x4=32x1-3x2+x3+5x4=5
矩阵求非齐次方程组 2*X1+X2-X3+X4=1 4*X1+2*X2-2*X3+X4=2 2*X1+X2-X3-X4=1 求解过程要用到矩阵的秩2*X1+X2-X3+X4=14*X1+2*X2-2*X3+X4=2 2*X1+X2-X3-X4=1 是这样的一个方程组求解
x1-x2+x3=1 x2+3x3=0 2x1+7x3=4用可莱姆法则增广矩阵求解方程组
齐次方程组,x1+4X2-3X3=0 2X1+5X2-3X3=0 X1+2X2-X3=0求其通解
方程组3x1+x2+x3
单纯形法求解下列线性规划模型minf=x1+2x2-x3st.2x1+x2-x3≤4X1-2X2+2X3≤8X1+X2+X3≤5X1.X2.X3≥0
求解齐次线性方程组...X1+X2+2X3-X4=0{ 2X1+X2+X3-X4=02X1+2X2+X3+2X4=0
求解线性方程组:X1+2X2+X3=8,2X1+3X2+X3=11,X1+3X2+3X3=16.
求下列齐次方程组的一个基础解系:x1+2x2+x3-x4=0,3x1+6x2-x3-3x4=0,5x1+10x2+x3-5x4=0
求方程组x1+3x2+x3+2x4+4x5=3 2x1-x2+8x3+7x4+2x5=9 4x1+5x2+6x3+11x4+10x5=15的全部解线性代数
mathematica如何求解含有三角函数的方程?FindRoot[{3 x1^3 + 2 x2 - 5 + Sin[x1 - x2] Sin[x1 + x2] == 0,-x1*Exp[x1 - x2] + x2 (4 + 3 x2^2) + 2 x3 + Sin[x2 - x3] Sin[x2 + x3] - 8 == 0,-x2*Exp[x2 - x3] + 4 x3 - 3 ==0},{x1,Pi/2},{x2,2},{x3,0}]
求解线性方程组 X1+X2+X3=6 2X1+3X2+X3=11 X1-X2+2X3=5