急、高中数列题(17:30前回答)已知数列 {an}的前n项和是Sn,且2Sn=2-an1. 求 {an}通项公式2. 记b n=an+n,求数列 {bn}的前n项和T n.
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![急、高中数列题(17:30前回答)已知数列 {an}的前n项和是Sn,且2Sn=2-an1. 求 {an}通项公式2. 记b n=an+n,求数列 {bn}的前n项和T n.](/uploads/image/z/1092290-50-0.jpg?t=%E6%80%A5%E3%80%81%E9%AB%98%E4%B8%AD%E6%95%B0%E5%88%97%E9%A2%98%EF%BC%8817%3A30%E5%89%8D%E5%9B%9E%E7%AD%94%EF%BC%89%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97+%7Ban%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E6%98%AFSn%2C%E4%B8%942Sn%3D2-an1.+%E6%B1%82+%7Ban%7D%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F2.+%E8%AE%B0b+n%3Dan%2Bn%2C%E6%B1%82%E6%95%B0%E5%88%97+%7Bbn%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8CT+n.)
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