已知正方形ABCD中,E为对角线BD上一点,过E点作EF⊥BD交BC于F,连接DF,G为DF中点,连接EG,CG.(1)求证:EG=CG(2)将图①中△BEF绕B点逆时针旋转45°,如图②所示,取DF中点G,连接EG,CG,问(1)中的结论是
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/09 08:09:14
![已知正方形ABCD中,E为对角线BD上一点,过E点作EF⊥BD交BC于F,连接DF,G为DF中点,连接EG,CG.(1)求证:EG=CG(2)将图①中△BEF绕B点逆时针旋转45°,如图②所示,取DF中点G,连接EG,CG,问(1)中的结论是](/uploads/image/z/11200448-56-8.jpg?t=%E5%B7%B2%E7%9F%A5%E6%AD%A3%E6%96%B9%E5%BD%A2ABCD%E4%B8%AD%2CE%E4%B8%BA%E5%AF%B9%E8%A7%92%E7%BA%BFBD%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E8%BF%87E%E7%82%B9%E4%BD%9CEF%E2%8A%A5BD%E4%BA%A4BC%E4%BA%8EF%2C%E8%BF%9E%E6%8E%A5DF%2CG%E4%B8%BADF%E4%B8%AD%E7%82%B9%2C%E8%BF%9E%E6%8E%A5EG%2CCG.%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9AEG%3DCG%EF%BC%882%EF%BC%89%E5%B0%86%E5%9B%BE%E2%91%A0%E4%B8%AD%E2%96%B3BEF%E7%BB%95B%E7%82%B9%E9%80%86%E6%97%B6%E9%92%88%E6%97%8B%E8%BD%AC45%C2%B0%2C%E5%A6%82%E5%9B%BE%E2%91%A1%E6%89%80%E7%A4%BA%2C%E5%8F%96DF%E4%B8%AD%E7%82%B9G%2C%E8%BF%9E%E6%8E%A5EG%2CCG%2C%E9%97%AE%EF%BC%881%EF%BC%89%E4%B8%AD%E7%9A%84%E7%BB%93%E8%AE%BA%E6%98%AF)
xVnW(UDf5v0K&U>ob_TO!sOaU5},9gp_*jl!OpzUsQka^Q*a689o=ށڛ <O8ă:'z
LɓaðMTJq&صoh/&Qi̛wc@S[8ojZZF$+'u6chB
GK
tOPfW#o;0%P>gL,bLx~cGixf E.Ģ
VPąV O*nMjN7
P5U&m˻
#swGfdx+OB<>ruǟ+Gщط.24:ː4,~F$yIpDIh@^<_h@Q$3.Rq3\4-R(M22E>:JiM@Q.XX],nQVQHE"Qx(QP X@.W||e'
'u0=tRw Kce$