已知正方形ABCD中,E为对角线BD上一点,过E点作EF垂直BD交BC于F已知正方形ABCD中,E为对角线BD上一点,过E点做EF⊥BD交BC于F,连接DF,G为DF中点,连接EG,CG2.将图1中△BEF绕B点逆时针旋转45°,如图2所示,取DF
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![已知正方形ABCD中,E为对角线BD上一点,过E点作EF垂直BD交BC于F已知正方形ABCD中,E为对角线BD上一点,过E点做EF⊥BD交BC于F,连接DF,G为DF中点,连接EG,CG2.将图1中△BEF绕B点逆时针旋转45°,如图2所示,取DF](/uploads/image/z/14781609-9-9.jpg?t=%E5%B7%B2%E7%9F%A5%E6%AD%A3%E6%96%B9%E5%BD%A2ABCD%E4%B8%AD%2CE%E4%B8%BA%E5%AF%B9%E8%A7%92%E7%BA%BFBD%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E8%BF%87E%E7%82%B9%E4%BD%9CEF%E5%9E%82%E7%9B%B4BD%E4%BA%A4BC%E4%BA%8EF%E5%B7%B2%E7%9F%A5%E6%AD%A3%E6%96%B9%E5%BD%A2ABCD%E4%B8%AD%2CE%E4%B8%BA%E5%AF%B9%E8%A7%92%E7%BA%BFBD%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E8%BF%87E%E7%82%B9%E5%81%9AEF%E2%8A%A5BD%E4%BA%A4BC%E4%BA%8EF%2C%E8%BF%9E%E6%8E%A5DF%2CG%E4%B8%BADF%E4%B8%AD%E7%82%B9%2C%E8%BF%9E%E6%8E%A5EG%2CCG2.%E5%B0%86%E5%9B%BE1%E4%B8%AD%E2%96%B3BEF%E7%BB%95B%E7%82%B9%E9%80%86%E6%97%B6%E9%92%88%E6%97%8B%E8%BD%AC45%C2%B0%2C%E5%A6%82%E5%9B%BE2%E6%89%80%E7%A4%BA%2C%E5%8F%96DF)
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