有图AB=AD,CD⊥AB,BE⊥AC,BE与CD相交于点F,求证：AF平分∠BAC.

ab⊥ac.ad⊥ae .ab=ac .ad=ae .说明 be⊥cd 如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证BE⊥CD 如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证BE⊥CD 有图AB=AD,CD⊥AB,BE⊥AC,BE与CD相交于点F,求证：AF平分∠BAC. 有图 AB=AD,CD⊥AB,BE⊥AC,BE与CD相交于点F,求证：AF平分∠BAC. 已知,如图,AB⊥AC,AB=AC,AD⊥'AE,AD=AE,求证:(1)BE=CD;(2)BC⊥CD急!帮个忙呗! 已知:如图AC⊥BD,AB‖CD,AB=CD.求证:AD=AB 在△ABC中,AD⊥AB,AD=AB,AE⊥AC,AE=AC,求证：BE=CD 如图所示,AD⊥AB,AE⊥AC,且AD=AB,AE=AC.试说明:BE=CD,BE⊥CD 如图所示,AD⊥AB,AE⊥AC,且AD=AB,AE=AC.试说明:BE=CD,BE⊥CD 如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE,求证:(1)△DAC≌△EAB;(2)BE⊥CD. ,の 如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE,已知△DAC≌△EAB.求证BE⊥CD 如图,已知AB⊥AC,AD⊥AE,且AB=AC,AD=AE.BE和CD的位置关系如何?并说明理由 如图,已知AB⊥AC,AD⊥AE,且AB=AC,AD=AE,BE与CD的位置关系如何? 如图,直角梯形ABCD,CD‖AB,AB=AC,AE⊥AC,且AE=AD,连BE交AC于F,求证：BF=EF. 如图,直角梯形ABCD,CD‖AB,AB=AC,AE⊥AC,且AE=AD,连BE交AC于F,求证：BF=EF. 如图,CD⊥AB,BE⊥AC,垂足分别为D、E,BE交CD于F,且AD=DF,求证：AC=BF 如图,∠DCE=90°.CD=CE,AD⊥AC,BE⊥AC,垂足分别为A、B,试说明AD+AB=BE