如图AD为△ABC的角平分线,M为BC的中点,ME//DA交BA的延长线于E.你能运用“中线倍长的转化思想证明BE=CF=½(AD+AC)吗?试试看.
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![如图AD为△ABC的角平分线,M为BC的中点,ME//DA交BA的延长线于E.你能运用“中线倍长的转化思想证明BE=CF=½(AD+AC)吗?试试看.](/uploads/image/z/11325393-9-3.jpg?t=%E5%A6%82%E5%9B%BEAD%E4%B8%BA%E2%96%B3ABC%E7%9A%84%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%2CM%E4%B8%BABC%E7%9A%84%E4%B8%AD%E7%82%B9%2CME%2F%2FDA%E4%BA%A4BA%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8EE.%E4%BD%A0%E8%83%BD%E8%BF%90%E7%94%A8%E2%80%9C%E4%B8%AD%E7%BA%BF%E5%80%8D%E9%95%BF%E7%9A%84%E8%BD%AC%E5%8C%96%E6%80%9D%E6%83%B3%E8%AF%81%E6%98%8EBE%3DCF%3D%26%23189%3B%EF%BC%88AD%2BAC%EF%BC%89%E5%90%97%3F%E8%AF%95%E8%AF%95%E7%9C%8B.)
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