对数log(a^n)M=1/n×log(a) M怎么证明?只能 用换底公式证明么?
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对数log(a^n)M=1/n×log(a) M怎么证明?只能 用换底公式证明么?
对数log(a^n)M=1/n×log(a) M怎么证明?
只能 用换底公式证明么?
对数log(a^n)M=1/n×log(a) M怎么证明?只能 用换底公式证明么?
换底公式:
log(a^n)M=loga(M)/loga(a^n)=loga(M)/n=1/n*loga(M).
log(a^n)M=log(a^n) (M^n)^1/n=1/n×log(a^n)M^n=1/n×log(a) M
log(a^n)M =loga(M)/loga(a^n) =loga(M)/n 即log(a^n)M=1/n×log(a) M 换底公式loga(b)=logx(b)/logx(a)这里是以x为底换的我做的
证明对数运算法则(1)log(a)(MN)=log(a)(M)+log(a)(N); (2)log(a)(M/N)=log(a)(M)-log(a)(N);(1)log(a)(MN)=log(a)(M)+log(a)(N); (2)log(a)(M/N)=log(a)(M)-log(a)(N); (3)log(a)(M^n)=nlog(a)(M) (n∈R)
log(a^n)M=1/n×log(a) M,用对数换底公式怎么证明
对数log(a^n)M=1/n×log(a) M怎么证明?只能 用换底公式证明么?
对数运算有这样的公式么?log(a^n)(M)=1/n*log(a)(M)
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