log(a^n)M= 1/n log(a)(M) log(a^n)M= n log(a)(M) 哪个对啊求神回复

log(a)M+log(a)N=? 证明a(log(m)n)=n(log(m)a) log a (m^n)=(log a m)^n? log(a^n)M= 1/n log(a)(M) log(a^n)M= n log(a)(M) 哪个对啊求神回复 证明对数运算法则（1）log(a)(MN)=log(a)(M)+log(a)(N); 　　（2）log(a)(M/N)=log(a)(M)-log(a)(N);（1）log(a)(MN)=log(a)(M)+log(a)(N); 　　（2）log(a)(M/N)=log(a)(M)-log(a)(N); 　　（3）log(a)(M^n)=nlog(a)(M) （n∈R） 求证 log(a) (M·N)=log(a) M+log(a) N log(下标a)(M*N)是什么意思?= log(下标a)M+log(下标a)N 为什么log(a^n)(M)=1/n×log(a)(M) 推导log(a)(M/N) log(a^n)(M)=1/nlog(a)(M).. log(a)(mn)=log(a)(m)+log(a)(n)为什么呀? 换底公式推导过程1.log(a)(b)=1/log(b)(a) 2.log(a^n)(b^m)=m/n*[log(a)(b)] 3.log(a)(M^n)=nlog(a)(M) 求对数函数公式的推导log(a)(M^n)=nlog(a)(M) 和log(a)(N)=log(b)(N) / log(b)(a) 的推导 证明log(a^m)b^n=(n/m)log(a)b log a^m(b^n)=(n/m)*log a(b) log(a^n)M=1/n×log(a) M,用对数换底公式怎么证明 对数log(a^n)M=1/n×log(a) M怎么证明?只能 用换底公式证明么？ 对数运算有这样的公式么?log(a^n)(M)=1/n*log(a)(M)