(x-1/2y-1)(x-1/2y+1)-(x-1/2y-1)^2,其中x=1.5,y=3.9
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(x-1/2y-1)(x-1/2y+1)-(x-1/2y-1)^2,其中x=1.5,y=3.9
(x-1/2y-1)(x-1/2y+1)-(x-1/2y-1)^2,其中x=1.5,y=3.9
(x-1/2y-1)(x-1/2y+1)-(x-1/2y-1)^2,其中x=1.5,y=3.9
这是整式吧
(x-1/2y-1)(x-1/2y+1)-(x-1/2y-1)^2
=(x-1/2y-1)[(x-1/2y+1)-(x-1/2y-1)]
=(x-1/2y-1)*2
=2x-y-2
∵x=1.5,y=3.9
∴原式=2×1.5-3.9-2=-2.9
不知道分母是什么,路过拿分走人
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