一个极限求和问题?1/根(2n-1) + 1/[根(2n-1)+根(4n-4)] + 1/[根(4n-4)+根(6n-9)] + ...+ 1/[根(2(i-1)n-(i-1)^2)+根(2in-i^2)] + ...+ 1/[根(2(n-1)*n-(n-1)^2)+根(2n*n-n^2)] 当n趋于无穷大时此式极限为什么为π/4
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![一个极限求和问题?1/根(2n-1) + 1/[根(2n-1)+根(4n-4)] + 1/[根(4n-4)+根(6n-9)] + ...+ 1/[根(2(i-1)n-(i-1)^2)+根(2in-i^2)] + ...+ 1/[根(2(n-1)*n-(n-1)^2)+根(2n*n-n^2)] 当n趋于无穷大时此式极限为什么为π/4](/uploads/image/z/11468432-56-2.jpg?t=%E4%B8%80%E4%B8%AA%E6%9E%81%E9%99%90%E6%B1%82%E5%92%8C%E9%97%AE%E9%A2%98%3F1%2F%E6%A0%B9%282n-1%29+%2B+1%2F%5B%E6%A0%B9%282n-1%29%2B%E6%A0%B9%284n-4%29%5D+%2B+1%2F%5B%E6%A0%B9%284n-4%29%2B%E6%A0%B9%286n-9%29%5D+%2B+...%2B+1%2F%5B%E6%A0%B9%EF%BC%882%28i-1%29n-%28i-1%29%5E2%29%2B%E6%A0%B9%282in-i%5E2%29%5D+%2B+...%2B+1%2F%5B%E6%A0%B9%282%28n-1%29%2An-%28n-1%29%5E2%29%2B%E6%A0%B9%282n%2An-n%5E2%29%5D+%E5%BD%93n%E8%B6%8B%E4%BA%8E%E6%97%A0%E7%A9%B7%E5%A4%A7%E6%97%B6%E6%AD%A4%E5%BC%8F%E6%9E%81%E9%99%90%E4%B8%BA%E4%BB%80%E4%B9%88%E4%B8%BA%CF%80%2F4)
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