求点到直线间的距离(1)A(2,3) 2x-y+4=0 (2)B(-5,7) 12x+5y-1=0(3)C(-1,4) x-2=0 (4)平行直线3x+4y-10=0和6x+8y-7=0
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![求点到直线间的距离(1)A(2,3) 2x-y+4=0 (2)B(-5,7) 12x+5y-1=0(3)C(-1,4) x-2=0 (4)平行直线3x+4y-10=0和6x+8y-7=0](/uploads/image/z/11470980-12-0.jpg?t=%E6%B1%82%E7%82%B9%E5%88%B0%E7%9B%B4%E7%BA%BF%E9%97%B4%E7%9A%84%E8%B7%9D%E7%A6%BB%EF%BC%881%EF%BC%89A%EF%BC%882%2C3%EF%BC%89+2x-y%2B4%3D0+%EF%BC%882%EF%BC%89B%EF%BC%88-5%2C7%EF%BC%89+12x%2B5y-1%3D0%EF%BC%883%EF%BC%89C%EF%BC%88-1%2C4%EF%BC%89+x-2%3D0+%EF%BC%884%EF%BC%89%E5%B9%B3%E8%A1%8C%E7%9B%B4%E7%BA%BF3x%2B4y-10%3D0%E5%92%8C6x%2B8y-7%3D0)
求点到直线间的距离(1)A(2,3) 2x-y+4=0 (2)B(-5,7) 12x+5y-1=0(3)C(-1,4) x-2=0 (4)平行直线3x+4y-10=0和6x+8y-7=0
求点到直线间的距离(1)A(2,3) 2x-y+4=0 (2)B(-5,7) 12x+5y-1=0
(3)C(-1,4) x-2=0 (4)平行直线3x+4y-10=0和6x+8y-7=0
求点到直线间的距离(1)A(2,3) 2x-y+4=0 (2)B(-5,7) 12x+5y-1=0(3)C(-1,4) x-2=0 (4)平行直线3x+4y-10=0和6x+8y-7=0
(1) 点A(2,4)到直线2x - y + 4 = 0的距离
d = | 2×2 + 3×(-1)+4|/√[2^2 + (-1)^2) = √5
(2) 点B(-5,7)到直线12x + 5y -1 = 0的距离是
d = | 12×(-5) + 5×7 - 1|/√(12^2 + 5^2) = 2
(3) 点C(-1,4)到直线 x - 2 = 0 的距离是
方法1 求C点的横坐标-1,到直线 x = 2的距离
d = | 2 - 1| = 3
方法2 用点到直线的距离公式
d = | 1×(-1) + 0 ×4 -2|/√(1^0 + 0^2) = 3
(4) 平行线3x + 4y - 10 = 0 到平行线6x + 8y -7 = 0
在直线3x + 4y - 10 = 0 上任取一点,如x = 0 y = 5/2,即点(0,5/2)
点(0,5/2)到直线6x + 8y - 7 = 0 的距离
d = | 6×0 + 8×(5/2) - 7|/√(6^2 + 8^2) = 13/10