已知数列{an}的前n项和Sn=-an-1/2^n-1+2(n为整数)(1)令bn=2^an,求证数列{bn}是等差数列,并求数列{an}的通项公式(2)令bn=n+1/n•an,求Tn=C1+C2+……+Cn
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![已知数列{an}的前n项和Sn=-an-1/2^n-1+2(n为整数)(1)令bn=2^an,求证数列{bn}是等差数列,并求数列{an}的通项公式(2)令bn=n+1/n•an,求Tn=C1+C2+……+Cn](/uploads/image/z/11516805-45-5.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8CSn%3D-an-1%2F2%5En-1%2B2%EF%BC%88n%E4%B8%BA%E6%95%B4%E6%95%B0%EF%BC%89%EF%BC%881%EF%BC%89%E4%BB%A4bn%3D2%5Ean%2C%E6%B1%82%E8%AF%81%E6%95%B0%E5%88%97%7Bbn%7D%E6%98%AF%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%2C%E5%B9%B6%E6%B1%82%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%EF%BC%882%EF%BC%89%E4%BB%A4bn%3Dn%2B1%2Fn%26%238226%3Ban%2C%E6%B1%82Tn%3DC1%2BC2%2B%E2%80%A6%E2%80%A6%2BCn)
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已知数列{an}的前n项和Sn=-an-1/2^n-1+2(n为整数)(1)令bn=2^an,求证数列{bn}是等差数列,并求数列{an}的通项公式(2)令bn=n+1/n•an,求Tn=C1+C2+……+Cn
已知数列{an}的前n项和Sn=-an-1/2^n-1+2(n为整数)
(1)令bn=2^an,求证数列{bn}是等差数列,并求数列{an}的通项公式
(2)令bn=n+1/n•an,求Tn=C1+C2+……+Cn
已知数列{an}的前n项和Sn=-an-1/2^n-1+2(n为整数)(1)令bn=2^an,求证数列{bn}是等差数列,并求数列{an}的通项公式(2)令bn=n+1/n•an,求Tn=C1+C2+……+Cn
用把bn、bn-1代入Sn-Sn-1=an中.
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