(sinx/2)^6+(cosx/2)^6+3最小正周期!
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/08 09:23:01
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(sinx/2)^6+(cosx/2)^6+3最小正周期!
(sinx/2)^6+(cosx/2)^6+3最小正周期!
(sinx/2)^6+(cosx/2)^6+3最小正周期!
(sinx/2)^6+(cosx/2)^6+3
=[(sinx/2)^2+(cosx/2)^2][(sinx/2)^4-(sinx/2)^2(cosx/2)^2+(cosx/2)^4]+3
=[(sinx/2)^2+(cosx/2)^2]^2-3(sinx/2)^2(cosx/2)^2+3
=1-3/4(sinx)^2+3
=4-3/4*(1-cos2x)/2
=29/8+3/8cos2x
最小正周期T=2Pai/2=Pai
化简cosx^4+sinx^4+sinx^2cosx^2/(sinx^6+cosx^6+2sinx^2cosx^2)
化简(cosx^4+sinx^4+sinx^2cosx^2)/(sinx^6+cosx^6+2sinx^2cosx^2)
(cosx+2sinx)(cosx-sinx)+sinx2cosx 化简
(sinx+cosx)/(2sinx-cosx)=
y=sinx*sinx+2sinx*cosx
-sinx/2*cosx/2
证明:2(cosx-sinx)/1+sinx+cosx=cosx/1+sinx-sinx/1+cosx
证明:【2(cosx-sinx)】/(1+sinx+cosx)=cosx/(1+sinx) -sinx/(1+cosx)
求证cosX/(1+sinx)-sinx/(1+cosx)=2(cosx-sinx)/(1+sinx+cosx)
求证:(1+sinx+cosx)/(1+sinx-cosx)-(1+sinx-cosx)/(1+sinx+cosx)=2/tanx
求证:2(sinx-cosx)/(1+sinx+cosx)=sinx/(1+cosx)-cosx/(1+sinx)
求证:cosx/1+sinx-sinx/1+cosx=2(cosx-sinx)/1+sinx+cosx
求证.[(1+sinx+cosx+2sinx cosx)/(1+sinx+cosx)]=sinx+cosx
证明:2(cosx-sinx)/1+sinx+cosx=cosx/1+sinx-sinx/1+cosx
化简((sinx+cosx -1)(sinx-cosx+1)-2cosx)/sin2x
化简((sinx+cosx-1)(sinx-cosx+1)-2cosx)/sin2x
化简:(sinx)^2/(sinx-cosx)-(sinx+cosx)/((tanx)^2-1)
化简:根号2*cosx-根号6sinx