设log3 (2)=log2 (3^x),则x=你们全错了
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设log3 (2)=log2 (3^x),则x=你们全错了
设log3 (2)=log2 (3^x),则x=
你们全错了
设log3 (2)=log2 (3^x),则x=你们全错了
log3 (2)=log2 (3^x)=x*log2 (3)
x=log3 (2)/log2 (3)
=[log3(2)]^2
x=log3 (2)/log2 (3)
log3 (2)=log2 (3^x)
换成常用对数,得
lg2/lg3 = xlg3/lg2
x = lg²2 / lg²3
[log3(2]^2
设log3 (2)=log2 (3^x),则x=你们全错了
log2(3)+log3(5)+log3(2)=?
(log2 6)×(log3 6)-(log2 3+log3 2)=
(log2 6)×(log3 6)-(log2 3+log3 2)=
log2(3)*log3(2)=?
(log3^2)(log2^3)=
设p=log2*3,q=log3*2,r=log2*(log3*2),则大小关系为
已知log3(2) =log2(3)^x .求x
对数函数方程log3 2=log2 3^x
设p=log2(3)、Q=log2【log3(2)】、R=log2【log3(2)】,则它们的大小关系
解方程log2【9^2-4】=log2【3^x-2】+3答案是log3【6】
解方程:log4{2log3[1+log2(1+3log2 x)]}=1/2
为什么log3(2)=1/log2(3).
设log2(3)=t,log3(4)=?
设log3(2)=a,则log2(9)=?
设a=log2π,b=log2√3,c= log3√2比较大小
设p=log2(3)、Q=log3(2)、R=log2【log3(2)】,则它们的大小关系
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X