bn=(n+1)2n,求数列{bn/1}的前n项和Tn

数列b(n+1)=bn+ 2^n.求bn. 已知数列{ bn } 满足2b(n+1)= bn + 1/bn ,且bn>1,求{bn}通项公式 数列{bn}中,b1=1,b(n+1)^2-bn^2=2,求bn 数列b1=3,bn+1=3bn+2n,求bn通项. bn=(n+1)2n,求数列{bn/1}的前n项和Tn 数列{bn}满足bn=(2n-1)/3^n,求前n项和,Tn 数列bn的通项公式为bn=2/n*(n-1),求bn的前n项和. 数列b1=2,b(n+1)=bn+2^(2n+1）,求bn 已知数列{bn}=n(n+1),求数列{bn的前n项和Sn bn=(2n-1)/(n2^n) 求数列bn项max. 已知数列{bn}满足b1=-1,b(n+1)=bn+(2n-1),求bn 正数列{bn}前n项和Sn·且Sn=1/2(bn+n/bn)求Sn 数列bn的前n项和为Tn,6Tn=(3n+1)bn+2,求bn 已知数列bn满足bn=b^2n,其前n项和为Tn,求(1-bn)/Tn bn=1/(2n-1)(2n+1),数列bn的前n项和为Bn,求证,Bn 若数列bn满足bn=n^2/2^(n+1),证明bn 设数列{bn}满足bn=n^2/2^(n+1),证明:bn 若数列bn满足b1=2,且bn+1=bn+2^n+n,求数列bn的通项公式.